If a centrifugal pump develops 600 gallons per minute (gpm) at 350 feet of head, how much pounds per square inch (psi) is developed at 600 gpm when pumping JP-8?

To determine how much pressure in pounds per square inch (psi) is developed by a centrifugal pump at a specific flow rate, we can start by converting the pump's head in feet to psi. The relationship between feet of head and psi is defined by the equation:

1 psi = 2.31 feet of head.

Given that the pump develops 350 feet of head, we can convert this height by dividing by 2.31:

350 feet / 2.31 = approximately 151.5 psi.

However, the original question specifies the pump's performance at 600 gallons per minute, which requires consideration of how the flow rate affects the pressure developed. For a centrifugal pump, as flow increases, the pressure will typically drop.

In practical scenarios, the specific weight of the fluid being pumped, in this case JP-8, must also be taken into account, as it has a specific gravity affecting how head and pressure relate. The density of JP-8 is approximately 6.7 lb/US gallon.

Using this knowledge, the pressure can be re-evaluated at 600 gpm by directly calculating the pressure based on the head produced at this flow, which can vary depending on the pump's specific performance curve and characteristics.